The lines x = -3 and y = -4 intersect at the point ___.

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Solution

The line x = -3 is parallel to the y-axis and the line y = -4 is parallel to the x - axis.

Hence x = -3 and y = -4 intersect at the point P(-3, -4).

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\frac{x - 4}{2} = \frac{y + 5}{4} = \frac{z - 1}{- 3}

\frac{x - 2}{1} = \frac{y + 1}{3} = \frac{z}{2}

\frac{x + 1}{- 10} = \frac{y + 3}{- 1} = \frac{z - 4}{1}

\frac{x + 10}{- 1} = \frac{y + 1}{- 3} = \frac{z - 1}{4}

\frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4}

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The point of intersection of the lines x = 4 and y = -3 is ________.

(- 4, 3)

x + y = 2, x - y = 2

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