The linkage map of X-chromosome of fruitfly has 66 unit with yellow body gene (y) at one end and bobbed hair (b) gene at the other end. The recombination frequency between these two gene (y and b) should be a) 66% b)greater than 50% c) less than equal to 50% d)100 %

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The linkage map of the X-chromosome of fruit flies has 66 units, with yellow body gene (y) at one end and bobbed hair (b) gene at the other end. The recombination frequency between these two genes (y and b) should be :

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