The liquid filled in a cuboidal tin $60 c m \times 15 c m \times 12 c m$ is poured into a cylinder with area of base $540 c m^{2}$ . Find the height of the liquid in the cylinder.

10 c m

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40 c m

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200 c m

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20 c m

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Solution

The correct option is D $20 c m$
Volume of tin $= 60 \times 50 \times 12 = 10800 {c m}^{3}$
Volume of cylinder $=$ area of base $\times h$
$\Rightarrow 10800 = 540 \times h \Rightarrow h = \frac{10800}{540} = 20 c m$

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The liquid filled in a cuboidal tin 60cm×15cm×12cm is poured into a cylinder with area of base 540cm2. Find the height of the liquid in the cylinder.

The correct option is D 20cmVolume of tin =60×50×12=10800cm3Volume of cylinder = area of base ×h⇒10800=540×h⇒h=10800540=20cm

The liquid filled in a cuboidal tin $60 c m \times 15 c m \times 12 c m$ is poured into a cylinder with area of base $540 c m^{2}$ . Find the height of the liquid in the cylinder.

The correct option is D $20 c m$
Volume of tin $= 60 \times 50 \times 12 = 10800 {c m}^{3}$
Volume of cylinder $=$ area of base $\times h$
$\Rightarrow 10800 = 540 \times h \Rightarrow h = \frac{10800}{540} = 20 c m$