The liquid shown in figure in two arm are mercury (specific gravity = 13.6) and water if the difference of height of the mercury column is 2 cm find the height h of the water column.

30 cm

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33 cm

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27 cm

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24 cm

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Solution

The correct option is C
27 cm

Pressure at $A = P_{0} + h (1000) \times g$

Pressure at $B = P_{0} + (0.02) \times (13600) \times g$

As same level $P_{A} = P_{B}$

H=(0.02m)(13.6)

h = 0.27m

h = 27cm

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Similar questions

The liquids shown in figure in the two arms are mercury (specific gravity = 13.6) and water. if the difference of heights of the mercury columns is 2 cm, find the height h of the water column.

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The liquids shown in figure in the two arms are mercury (specific gravity = 13.6) and water. if the difference of heights of the mercury columns is 2 cm, find the height h of the water column.

Q. The liquids shown in figure in the two arms are mercury (specific gravity

13.6

) and water. If the heights of the mercury column and water column is as shown, find the height

h

of the water column.

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The liquid shown in figure in two arm are mercury (specific gravity = 13.6) and water if the difference of height of the mercury column is 2 cm find the height h of the water column.

The correct option is C 27 cm Pressure at A=P0+h(1000)×g Pressure at B=P0+(0.02)×(13600)×g As same level PA=PB H=(0.02m)(13.6) h = 0.27m h = 27cm

The correct option is C
27 cm

Pressure at $A = P_{0} + h (1000) \times g$

Pressure at $B = P_{0} + (0.02) \times (13600) \times g$

As same level $P_{A} = P_{B}$

H=(0.02m)(13.6)

h = 0.27m

h = 27cm