Question

The load versus elongation graph for four wires of same length and made of the same material are shown in the figure. The thinnest wire is represented by the line

• A. $\text{OA}$
• B. $\text{OC}$
• C. $\text{OD}$
• D. $\text{OB}$

Answer 1

The correct option is A $\text{OA}$

As we know, $\Delta L=\frac{FL}{AY}$
$\Rightarrow \Delta L\propto \frac{1}{A}$ [since $L,Y,F$ are constant]
For the same value of load, thin wire will stretch more than a thick wire. [because $A$ is less]


From the graph, it is clear that for the same value of load, elongation is maximum for wire $\text{OA}$.
Hence, $\text{OA}$ is the thinnest wire among the four wires.