The lock of a safe consists of five disce each of which features the digits. 0,1,2,.....9. The safe can be opened by dialing a special combination og the digits. The number of days sufficient enough to open the safe, if the work day lasts 13h and 5s are needed to dial one combination of digits is:

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Solution

The correct option is B 10
$w e h a v e . . . . . . . D i g i t s = D_{1} D_{2} D_{3} D_{4} D_{5} 1010101010$
$T o t a l N o . C o d e = 100000 T o t a l T i m e = 500000 s e c o n d s W o r k i n g h o u r s = 10 \times 13 h o u r s = 130 \times 60 \times 60 = 468000 s c e o n d s . S o, t h e c o r r e c t o p t i o n i s B = 10$

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The lock of a safe consists of five disce each of which features the digits. 0,1,2,.....9. The safe can be opened by dialing a special combination og the digits. The number of days sufficient enough to open the safe, if the work day lasts 13h and 5s are needed to dial one combination of digits is:

The correct option is B 10we have.......Digits=D1D2D3D4D51010101010TotalNo.Code=100000TotalTime=500000secondsWorkinghours=10×13hours=130×60×60=468000sceonds.So,thecorrectoptionisB=10