The locus of a point (α,β) moving under the condition that y=αx+β is a tangent to the hyperbola x2a2−y2b2=1 is :
A
a circle
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B
an ellipse
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C
a hyperbola
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D
a parabola
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Solution
The correct option is C a hyperbola Tangent to the hyperbola x2a2−y2b2=1 y=mx±√a2m2−b2 and it is given that , y=αx+β is the tangent to the hyperbola m=αanda2m2−b2=β2 a2α2−b2=β2 Locus is a2x2−b2=y2 which is hyperbola Hence, Option C.