The locus of a point equidistant from three collinear points is:
A
A straight line
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B
A pair of points
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C
A point
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D
The null set
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Solution
The correct option is D The null set Let three collinear points be (a,0), (b,0) and (0,0). Let the point (x,y) be equidistant from these collinear points. ⇒(x−a)2+y2=(x−b)2+y2=x2+y2⇒a2−2ax=b2−2bx=0⇒x=a2=b2⇒a=b
This contradicts the uniqueness of the points. Thus, no such (x,y) exists. Option D is answer.