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Question

The locus of a point such that difference of the squares of the tangents from it to two given circles is constant, is given by

A
A circle
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B
A line perpendicular to radical axis
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C
A line parallel to radical axis
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D
A pair of straight lines
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Solution

The correct option is D A line parallel to radical axis
So, PAPB=C
(s1)2(s2)2=c
s1s2=c
as we know, s1s2=0 is a equation of radical axis.
So, then s1s2=c is a equation of line parallel to
radical axis.
57493_31760_ans_8e80b92999d74abfa862fd2d48507936.png

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