The locus of a point such that difference of the squares of the tangents from it to two given circles is constant, is given by
A
A circle
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B
A line perpendicular to radical axis
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C
A line parallel to radical axis
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D
A pair of straight lines
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Solution
The correct option is D A line parallel to radical axis So, PA−PB=C (√s1)2−(√s2)2=c s1−s2=c as we know, s1−s2=0 is a equation of radical axis. So, then s1−s2=c is a equation of line parallel to radical axis.