The locus of a point which is equidistant from yz-plane and zx-plane is

x + y = 0

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x^{2} - y^{2} = 0

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x^{2} + y^{2} + z^{2} = 0

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x^{3} - y^{3} = 0

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Solution

The correct option is B $x^{2} - y^{2} = 0$
Let the point be $P (x, y, z)$ .
Its distance from $y z$ plane is ${(x^{2})}^{0.5}$
Its distance from $x z$ plane is ${(y^{2})}^{0.5}$
Since these 2 are equal,
$⟹ {(x^{2})}^{0.5}$ = ${(y^{2})}^{0.5}$
$⟹ x^{2} - y^{2} = 0$

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