The locus of a point,which moves in such a way that its distance from from the origin (0,0) is thrice the distance from x axis is ?
A
x2−8y2=0
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B
4x2−y2=0
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C
x2+8y2=0
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D
x2−4y2=0
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Solution
The correct option is Ax2−8y2=0 Let the point be (h,k). Distance from origin: √h2+k2 Distance from x-axis: |k| Given: √h2+k2=3|k| Squaring both sides: h2+k2=9k2 ⟹h2−8k2=0 Replacing (h,k)=(x,y) gives the required locus: x2−8y2=0