Question

The locus of a point which moves so that it is always equidistant from the point A(a, 0) and B (- a, 0) is

• A. A circle
• B. Perpendicular bisector of the line segment AB
• C. A line parallel to x-axis
• D. None of these

Answer 1

The correct option is B

Perpendicular bisector of the line segment AB

Let point be (h, k) then, $(h-a{)}^2+k^2=(h+a{)}^2+k^2$

$\Rightarrow$ 4ha = 0 $\Rightarrow$ h = 0. Hence x = 0.