Question

The locus of a point, whose abscissa and ordinate are always equal to

• A. $x+y=0$
• B. $x-y=0$
• C. $x+y=1$
• D. $x+y+1=0$

Answer 1

The correct option is B $x-y=0$

Let $p(x,y)$ be the point such that $x=y$

$x-y$ $=0$

so, locus of $p(x,y)$ is $(x-y)$ $=0$