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Question

The locus of centers of all circles passing through two given points A and B, is the perpendicular bisector the line segment AB.


A

True

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B

False

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Solution

The correct option is A

True


Let P and Q be the centers of two circles S and S’, each passing through two given points A and B. Then,

PA = PB [Radii of the same circle]

P lies on the perpendicular bisector of AB …(i)

Again, QA = QB [Radii of the same circle]

Q line on the perpendicular bisector of AB …(ii)

From (i) and (ii), it follows that P and Q both lie on the perpendicular bisector of AB.

Therefore, the locus of the centers of all the circles passing through A and B is the perpendicular bisector of AB.

Hence, the statement is correct.


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