The locus of centers of all circles passing through two given points A and B, is the perpendicular bisector the line segment AB.
True
Let P and Q be the centers of two circles S and S’, each passing through two given points A and B. Then,
PA = PB [Radii of the same circle]
⇒ P lies on the perpendicular bisector of AB …(i)
Again, QA = QB [Radii of the same circle]
⇒ Q line on the perpendicular bisector of AB …(ii)
From (i) and (ii), it follows that P and Q both lie on the perpendicular bisector of AB.
Therefore, the locus of the centers of all the circles passing through A and B is the perpendicular bisector of AB.
Hence, the statement is correct.