The locus of mid-point of line segment intercepted between real and imaginary axes by the line aĀÆĀÆĀÆz+ĀÆĀÆĀÆaz+b=0; where b is a real parameter and a is a fixed complex number with non- zero real and imaginary parts, is
A
az+¯¯¯az=0
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B
a¯¯¯z+¯¯¯az=0
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C
az+¯¯¯¯¯¯az=0
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D
az−¯¯¯az=0
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Solution
The correct option is Caz+¯¯¯¯¯¯az=0 Given equation of line is a¯¯¯z+¯¯¯az+b=0,∀b∈R
Let PQ be the segment intercepted between the axes.
For real intercept zR, zR=¯¯¯¯¯¯zR ⇒zR(a+¯¯¯a)+b=0 ⇒zR=−b(a+¯¯¯a)
For imaginary intercept zI, zI+¯¯¯¯¯zI=0 ⇒zI(¯¯¯a−a)+b=0 ⇒z1=−b¯¯¯a−a
Let locus of mid- point be z, then z=zR+zI2 =−b2[1¯¯¯a+a+1¯¯¯a−a] =¯¯¯ab(a+¯¯¯a)(a−¯¯¯a) =¯¯¯aba2−(¯¯¯a)2 ⇒z(a2−(¯¯¯a)2¯¯¯a)=b
As b is real parameter, ⇒z(a2−(¯¯¯a)2¯¯¯a)=¯¯¯z(a2−(¯¯¯a)2¯¯¯a) ⇒az+¯¯¯¯¯¯az=0