The locus of point of intersection of any tangent to the parabola $y^{2} = 4 a (x - 2)$ with a line perpendicular to it and passing through the focus, is

x = 2

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y = 0

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x = a

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x = a + 2

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Solution

The correct option is A x = 2
It is well known property of a parabola that a tangent and normal to it from focus intersect at tangent at vertex. The tangent at the vertex of the the given parabola is x = 2.

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Similar questions

y^{2} = 4 a (x - 2)

The locus of a point whose chord of contact with respect to parabola
$y^{2} = 8 x$ passes through focus is

y^{2} = p x

\frac{x}{3} + \frac{y}{2} = 1

\frac{x}{2} + \frac{y}{3} = 1

y^{2} = 4 a (x + a)

y^{2} = 4 b (x + b)

y^{2} = p x

\frac{x}{3} + \frac{y}{2} = 1

\frac{x}{2} + \frac{y}{3} = 1

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