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Point Form of Tangent: Ellipse

The locus of ...

Question

The locus of point of intersection of the two tangents to the ellipse $b^{2} x^{2} + a^{2} y^{2} = a^{2} b^{2}$ which makes an angle $60^{\circ}$ with one another is

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Solution

The correct option is A
$T a n θ = \frac{2 a b \sqrt{S_{11}}}{x_{1}^{2} + y_{1}^{2} - a^{2} - b^{2}}$

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Similar questions

b^{2} x^{2} + a^{2} y^{2} = a^{2} b^{2}

b^{2} x^{2} + a^{2} y^{2} = a^{2} b^{2}

θ_{1}

θ_{2}

cot θ_{1} + cot θ_{2} = t

b^{2} x^{2} + a^{2} y^{2} = a^{2} b^{2}

θ_{1}

θ_{2}

c o t θ_{1} + c o t θ_{2} = k

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

θ

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