The correct option is C 2y2=9ax
Given equation of parabola is
y2=4ax
A point on the parabola can be written in the parametric form as (at2,2at)
The equation of the tangent to parabola at the point "t" is
ty=x+at2 ....(1)
The equation of the tangent to parabola at the point "2t" is
2ty=x+4at2 ....(2)
Solving (1) and (2), we get
x=2at2
Put this value in (1), we get
y=3at
Point of intersection of tangents is (2at2,3at)
On substituting value of t, we get 2y2=9ax.