The locus of point of intersection of two tangents to y2=4ax at t and 2t on the parabola is
A
2y2=9ax
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B
4y2=9ax
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C
3y2=4ax
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D
3y2=8ax
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Solution
The correct option is A2y2=9ax Point of intersection of two tangents to y2=4ax at t and 2t is (2at2,3at) Let (h,k) be the locus So, 3at=k⇒t=k3a and h=2at2⇒h=2a(k3a)2 ⇒2k2=9ah ∴2y2=9ax