wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The locus of point z satisfying Re(1z)=k, where k is a non-zero real number is

A
a straight line
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a circle
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
an ellipse
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a hyperbola
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B a circle
Let z=x+iy, then
Re(1z)=kRe(1x+iy)=kRe(xiyx2+y2)=kxx2+y2=kx2+y2xk=0

Hence, the locus is a circle.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon