The locus of poles of chords of the ellipse x2a2-y2b2-1 which subtend a right angle at the centre of the ellipse- is-

The correct option is A x^2/a^4+y^2/b^4=1/a^2+1/b^2 ...

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Standard XII

Mathematics

Four Common Forms of Parabola Equation

The locus of ...

Question

The locus of poles of chords of the ellipse $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$ which subtend a right angle at the centre of the ellipse, is:

\frac{x^{2}}{a^{4}} + \frac{y^{2}}{b^{4}} = \frac{1}{a^{2}} + \frac{1}{b^{2}}

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\frac{x^{2}}{a^{4}} + \frac{y^{2}}{b^{4}} = \frac{2}{a^{2}} + \frac{2}{b^{2}}

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\frac{x^{2}}{a^{4}} - \frac{y^{2}}{b^{4}} = \frac{1}{a^{2}} - \frac{1}{b^{2}}

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\frac{x^{2}}{a^{4}} - \frac{y^{2}}{b^{4}} = \frac{1}{a^{2}} + \frac{1}{b^{2}}

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Solution

The correct option is A $\frac{x^{2}}{a^{4}} + \frac{y^{2}}{b^{4}} = \frac{1}{a^{2}} + \frac{1}{b^{2}}$

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Similar questions

If X = 1 - a^{2} and Y = 1 - b^{2}, then what is X^{2} + Y^{2} ?

Q. The locus of poles with respect to the ellipse

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

of any tangent to the auxilary circle is the curve

\frac{x^{2}}{a^{4}} + \frac{y^{2}}{b^{4}} = \frac{1}{c}

, then

c

is:

Equation of the locus of the pole with respect to the ellipse $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$ of any tangent line to the auxiliary circle is the curve
$\frac{x^{2}}{a^{4}} + \frac{y^{2}}{b^{4}} = λ^{2}$ where

p (θ), D (θ + \frac{π}{2})

are two points on the Ellipse

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

Then the locus of point of intersection of the two tangents at P and D to the ellipse is

Q. Which of the following is the common tangent to the ellipse

\frac{x^{2}}{a^{2} + b^{2}} + \frac{y^{2}}{b^{2}} = 1

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{a^{2} + b^{2}} = 1

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The locus of poles of chords of the ellipse x2a2+y2b2=1 which subtend a right angle at the centre of the ellipse, is:

The correct option is A x2a4+y2b4=1a2+1b2

The locus of poles of chords of the ellipse $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$ which subtend a right angle at the centre of the ellipse, is:

The correct option is A $\frac{x^{2}}{a^{4}} + \frac{y^{2}}{b^{4}} = \frac{1}{a^{2}} + \frac{1}{b^{2}}$