The locus of the centres of the circles passing through two fixed points A and B is
A
the circle whose diameter is AB
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B
the circle with a diameter perpendicular to AB
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C
the perpendicular bisector of the line AB
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D
none of the above
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Solution
The correct option is D the perpendicular bisector of the line AB Let O be the centre of a circle through two points A and B.Then OA=OB because they are radius of the circle .
Hence OAB is an isosceles triangle and the altitude from O to point P on AB defines two congnunt triangles OPA and OPB.
∴OP is the perpendicular bisector of AB.
Any point O on the perpendicular bisector likuoise defines two congnunt triangles.such that OA−OB