The locus of the centres of the circles which cut the circles x2+y2+4x−6y+9=0 and x2+y2−5x+4y−2=0 orthogonally is
9x + 10y - 7 = 0
x - y + 2 = 0
9x - 10y + 11 = 0
9x + 10y + 7 = 0
Required equation is S−S1=0 ⇒9x−10y+11=0
Tangents are drawn from the point P(1, 8) to the circle x2+y2−6x−4y−11=0 touch the circle at the point A and B, then equation of the circumcircle of the triangle PAB is