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Question

The locus of the equation x2+y2=0 is


A

A circle

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B

A hyperbola

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C

A pair of lines

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D

At the origin

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Solution

The correct option is D

At the origin


Explanation of the correct option.

Compute the locus:

Given : x2+y2=0

It can be written as, x2=-y2.

A perfect square can never be the same as the negative of another perfect square except at (0,0).

The loci of the given equation are at the origin.

Hence option D is the correct option.


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