The correct option is D (x2+y2)2=4c2xy
Equation of the tangent at (ct,ct) to the hyperbola xy=c2
is x+t2y=2ct
If (h,k) is the foot of perpendicular from the center (0,0)
on the tangent then −1t2+kh=−1
Also h=t2,k=2ct
Eliminating t we get the locus
(x2+y2)2=4c2xy