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Question

The locus of the foot of the perpendicular from the centre of the hyperbola xy=c2 on a variable tangent is :

A
(x2y2)2=4c2xy
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B
(x2+y2)2=2c2xy
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C
(x2y2)=4c2xy
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D
(x2+y2)2=4c2xy
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Solution

The correct option is D (x2+y2)2=4c2xy
Equation of the tangent at (ct,ct) to the hyperbola xy=c2
is x+t2y=2ct
If (h,k) is the foot of perpendicular from the center (0,0)
on the tangent then 1t2+kh=1
Also h=t2,k=2ct
Eliminating t we get the locus
(x2+y2)2=4c2xy

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