The locus of the mid-point of the chord of contact of tangents drawn from points lying on the straight line 4x-5y=20 to the circle x²+y²=9 is

$20 (x^{2} + y^{2})^{2} - 36 x + 45 y = 0$

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$20 (x^{2} + y^{2}) + 36 x - 45 y = 0$

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$36 (x^{2} + y^{2}) - 20 x + 45 y = 0$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$36 (x^{2} + y^{2}) + 20 x - 45 y = 0$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is A
$20 (x^{2} + y^{2})^{2} - 36 x + 45 y = 0$

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Similar questions

4 x - 5 y = 20

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