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Byju's Answer
Standard X
Mathematics
Summary: Trigonometry
the locus of ...
Question
the locus of the mid point of the portion of the tangent to the ellipse( x^2/a^2)+(y^2/b^2)=1 included between the coordinate axis is
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Solution
Dear student
p
a
r
a
m
e
t
r
i
c
e
q
u
a
t
i
o
n
o
f
tan
g
e
n
t
t
o
e
l
l
i
p
s
e
x
2
a
2
+
y
2
b
2
=
1
i
s
x
cos
θ
a
+
y
sin
θ
b
=
1
i
t
t
o
u
c
h
e
s
t
h
e
c
o
o
r
d
i
n
a
t
e
a
x
e
s
a
t
(
a
s
e
c
θ
,
0
)
a
n
d
(
0
,
b
cos
e
c
θ
)
l
e
t
t
h
e
m
i
d
p
o
i
n
t
o
f
p
o
r
t
i
o
n
o
f
tan
g
e
n
t
b
e
(
h
,
k
)
s
o
,
(
h
,
k
)
=
(
a
s
e
c
θ
/
2
,
b
cos
e
c
θ
/
2
)
w
h
i
c
h
i
s
m
i
d
p
o
i
n
t
o
f
(
a
s
e
c
θ
,
0
)
a
n
d
(
0
,
b
cos
e
c
θ
)
h
=
a
s
e
c
θ
/
2
g
i
v
e
s
cos
θ
=
a
/
2
h
k
=
b
c
o
s
e
c
θ
/
2
g
i
v
e
s
sin
θ
=
b
/
2
k
cos
2
θ
+
sin
2
θ
=
1
a
2
h
2
+
b
2
k
2
=
1
o
r
a
2
k
2
+
b
2
h
2
=
4
h
2
k
2
s
o
l
o
c
u
s
i
s
a
2
y
2
+
b
2
x
2
=
4
x
2
y
2
Regards
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Q.
The locus of the mid-point of the portion of a tangent to the ellipse
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