The locus of the middle points of chords of hyperbola 3x2−2y2+4x−6y=0 parallel to y=2x is :
A
3x−4y=4
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B
3x+4y=8
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C
5x−4y=9
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D
6x−3y=4
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Solution
The correct option is A3x−4y=4 By T=S1 the equation of chord whose midpoint is (h,k) is 3xh−2yk+2(x+h)−3(y+k)=3h2−2k2+4h−6k ⇒x(3h+2)−y(2k+3)−2h+3k−3h2+2k2=0
Its slope is 3h+22k+3=2 ∵ Its parallel to line y=2x ⇒3h−4k=4 ∴3x−4y=4