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Question

The locus of the middle points of chords of hyperbola 3x22y2+4x6y=0 parallel to y = 2x, is

A
3x – 4y = 4
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B
3y – 4x + 4 = 0
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C
4x – 4y = 3
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D
3x – 4y = 2
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Solution

The correct option is A 3x – 4y = 4
By T = S1, the equation of chord whose mid-point is (α,β) is 3xα2yβ+(x+α)2(y+β)=0
x(3α+2)y(2β+3)=2
as it is parallel to y = 2x
3α4β=4
Required locus is 3x – 4y = 4

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