The locus of the moving point P such that 2PA=3PB, where A is (0,0) and B is (4,−3), is
A
5x2+5y2+72x+54y+225=0
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B
5x2+5y2−72x−54y+225=0
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C
5x2+5y2−72x+54y+225=0
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D
5x2+5y2−72x+54y−225=0
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Solution
The correct option is C5x2+5y2−72x+54y+225=0 Let the coordinates of the point P be (α,β). Then, we have 2PA=3PB⇒4PA2=9PB2 ⇒4[(α−0)2+(β−0)2]=9[(α−4)2+(β+3)2] ⇒5α2+5β2−72α+54β+225=0 ∴ The locus of P is 5x2+5y2−72x+54y+225=0