The locus of the point of intersection of the lines, √2x−y+4√2k=0 and √2kx+ky−4√2=0 (k is any non-zero real parameter), is:
A
an ellipse whose eccentricity is 1√3.
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B
a hyperbola whose eccentricity is√3
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C
a hyperbola with length of its transverse axis 8√2
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D
an ellipse with length of its major axis 8√2
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Solution
The correct option is C a hyperbola with length of its transverse axis 8√2 √2x−y=−4√2k............(1)√2x+y=4√2k............(2)multiplying both equation(√2x+y)(√2x−y−4√2)=4√22x2−y2=−32y232−x216=1Hence, it represents a hyperbolae=√1+1632=√32Also, length of transverse axis =8√2