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Byju's Answer
Standard XII
Mathematics
Area of Triangle with Coordinates of Vertices Given
The locus of ...
Question
The locus of the point of intersection of the lines x cos
α
+
y
s
i
n
α
=
a
and
x
s
i
n
α
- y cos a = b, where
α
is parameter is
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Solution
x
c
o
s
α
+
y
s
i
n
α
=
a
×
s
i
n
α
⊖
x
s
i
n
α
−
y
c
o
s
α
=
b
×
c
o
s
α
y
(
s
i
n
2
α
+
c
o
s
2
α
)
=
a
s
i
n
α
−
b
c
o
s
α
⇒
y
=
a
s
i
n
α
−
b
c
o
s
α
x
c
o
s
α
+
y
s
i
n
α
=
a
×
c
o
s
α
⊕
x
s
i
n
α
−
y
c
o
s
α
=
b
×
s
i
n
α
x
(
−
c
o
s
2
α
+
s
i
n
2
α
)
=
a
c
o
s
α
+
b
s
i
n
α
⇒
x
=
a
c
o
s
α
+
b
s
i
n
α
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Similar questions
Q.
Find the LOCUS of point of intersection of the lines
x
cos
α
+
y
sin
α
=
a
and
x
sin
α
−
y
cos
α
=
b
, where
α
is a parameter.
Q.
Locus of point of intersection of the lines
x
cos
α
+
y
sin
α
=
a
and
x
sin
α
−
y
cos
α
=
b
, where
α
is a parameter is
Q.
The locus of the intersection of the lines
x
cos
α
+
y
sin
α
=
a
and
x
sin
α
−
y
cos
α
=
b
, where
α
is variable
Q.
Prove that the locus of the point of intersection of the lines
x
c
o
s
α
+
y
s
i
n
α
=
a
and
x
s
i
n
α
−
y
c
o
s
α
=
b
is a circle whatever
α
may be.
Q.
Whatever be the value of
α
, prove that the locus of the intersection of the straight lines
x
cos
α
+
y
sin
α
=
a
and
x
sin
α
−
y
cos
α
=
b
is a circle.
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Area of Triangle with Coordinates of Vertices Given
Standard XII Mathematics
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