The locus of the point of intersection of the straight lines xa+yb=K and xa−yb=1K where K is a non-zero real variable, is given by
A
a straight line
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B
an ellipse
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C
a parabola
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D
a hyperbola
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Solution
The correct option is D a hyperbola xa+yb=K.....................(i) Put (i) in this xa−yb=1K⇒xa−yb=1xa+yb⇒(xa−yb)(xa+yb)=1⇒(xa)2−(yb)2=1 Equation of hyperbola