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Question

The locus of the point of intersection of the tangents at the extremities of a chord of the circle
x2+y2=a2 which touches the circle x2+y2−2ax=0 passes through the point

A
(a2,0)
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B
(0,a2)
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C
(0,a)
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D
(a,0)
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Solution

The correct options are
A (a2,0)
B (0,a)
Let P(h,k) be the point of intersection of the tangents at the extremities of the chord AB of the circle x2+y2=a2
Since AB is the chord of contact of the tangents from P to this circle, its equation is hx+ky=a2
If this line touches the circle x2+y22ax=0,
then ha+k0a2h2+k2=±a
(ha)2=h2+k2
Therefore, the locus of (h,k) is (xa)2=x2+y2 or y2=a(a2x) which passes through the points given in (a) and (c)
Ans: A,C

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