The locus of the point of intersection of two perpendicular tangents to the hyperbola $\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1$ is :

directors circle

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{2} + y^{2} = a^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + y^{2} = a^{2} - b^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{2} + y^{2} = a^{2} + b^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
B $x^{2} + y^{2} = a^{2} - b^{2}$
C directors circle
The locus of the point of intersection of two perpendicular tangents to the hyperbola $\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1$ is director circle which is $x^{2} + y^{2} = a^{2} - b^{2}$
Ans: A,C

Suggest Corrections

Similar questions

The locus of the point of intersection of perpendicular tangents to the circles $x^{2} + y^{2} = a^{2} a n d x^{2} + y^{2} = b^{2} i s$

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

e > \sqrt{2}

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

x^{2} + y^{2} = a^{2} - b^{2}

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

x^{2} + y^{2} = a^{2} - b^{2}

x^{2}

y^{2}

a^{2}

x^{2}

y^{2}

b^{2}

p (θ), D (θ + \frac{π}{2})

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

Join BYJU'S Learning Program