The locus of z such that -z-z1-z-z2- - constant is

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The locus of ...

Question

The locus of z such that $| z - z_{1} | + | z - z_{2} | = λ$ (constant) is

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Similar questions

z

| z - z_{1} | - | z - z_{2} | = λ

∣ ∣ \frac{z + 1}{z - 1} ∣ ∣ = 1

∣ ∣ \frac{z - z_{1}}{z - z_{2}} ∣ ∣ = 1

z_{1}, z_{2}

z_{1} = 10 + 6 i, z_{2} = 4 + 2 i

arg (\frac{z - z_{1}}{z - z_{2}}) = \frac{π}{4},

z_{1}

z_{2}

z

\frac{z - z_{1}}{z - z_{2}} = e^{i θ}, θ \in R

| z - z_{1} | + | z - z_{2} | = k (> | z_{1} - z_{2} |)

z

z_{1}

z_{2}

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