The log- -logE graph between the de-Broglie wavelength - of an electron and its energy will be

The correct option is C λ=h/√(2mE)=h/√(2m).1/√(E) Taking log of both sides logλ= logh/√(2) m log√(E) log λ= 1/2logE+logh/√(2m) This is the equation of straig ...

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Byju's Answer

Standard XII

Physics

Stefan-Boltzman's Law

The logλ -log...

Question

The log $λ$ -log $E$ graph between the de-Broglie wavelength $λ$ of an electron and its energy will be

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Solution

The correct option is C

$λ = \frac{h}{\sqrt{2 m E}} = \frac{h}{\sqrt{2 m}} . \frac{1}{\sqrt{E}}$

Taking log of both sides

$l o g λ = l o g \frac{h}{\sqrt{2} m} - l o g \sqrt{E}$

$l o g λ = - \frac{1}{2} l o g E + l o g \frac{h}{\sqrt{2 m}}$

This is the equation of straight line having slope (-1/2) and positive intercept on $l o g λ$ axis

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