The logarithmic form of $4 = 2^{2}$ is

l o g_{2}^{4} = 2

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l o g_{2}^{2} = 2

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l o g_{2}^{4} = 4

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None of these

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Solution

The correct option is B $l o g_{2}^{2} = 2$
Since, $4 = 2^{2}$
$⟹ log$ of $4$ to base $2$ is $2$
$⟹ {log}_{2} 2 = 4$ .

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