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Question

The logic gate equivalent to the given logic circuit is-



A
NAND
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B
NOR
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C
AND
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D
OR
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Solution

The correct option is D OR
From, De Morgan's theorem

Y=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A¯¯¯¯B=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A+B=A+B=OR gate

Truth table for the given circuit as follows,
A B ¯¯¯¯A ¯¯¯¯B ¯¯¯¯¯¯¯¯¯¯¯¯¯¯A.¯¯¯¯B
0 0 1 1 0
0 1 1 0 1
1 0 0 1 1
1 1 0 0 1

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (B) is the correct answer.

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