The logic gates giving output '1' for the inputs of '1' and '0' are
A
AND and OR
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B
OR and NOR
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C
NAND and NOR
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D
NAND and OR
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E
AND and NOR
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Solution
The correct option is D NAND and OR Boolean expression of OR gate Y=A+B and Boolean expression of NAND gate Y=¯¯¯¯¯¯¯¯¯¯¯¯A⋅B i.e., the logic gate giving output 1 for the inputs of 1 and 0 are NAND and OR.