The logically equivalent proposition of p⇔q is
Lets form the truth table,
pqp⇔q(p∧q)∨(p∧q)(p∧q)∨(q⇒p)(p⇒q)∨(q⇒p)(p∧q)⇒(q∨p)TTTTTTTTFFTFFTFTFTTFTFFTFTTT
From the table, (p⇒q)∧(q⇒p) means p⇔q.
Hence, option is C is correct.
The contrapositive of p→ (~p∧q) is