Question

The longitudinal strain of a cylindrical bar of 25 mm diameter and 1.5 m length is found to be 3 times its lateral strain in a tensile test. What is the value of Bulk Modulus by assuming $E=1\times {10}^{5}N/m{m}^2?$

• A. $2\times {10}^{5}N/m{m}^2$
• B. $1.1\times {10}^{5}N/m{m}^2$
• C. $1\times {10}^{5}N/m{m}^2$
• D. $2\times {10}^{5}N/m{m}^2$

Answer 1

The correct option is C $1\times {10}^{5}N/m{m}^2$


$\epsilon =3{\epsilon }_y$
$\therefore \frac{{\epsilon }_y}{{\epsilon }_x}=\frac{1}{3}=\mu$
Now, $E=3K(1-2\mu )$
$K=\frac{E}{3(1-2\mu )}=1\times {10}^{5}N/m{m}^2$