The loop transfer function of a negative feedback system is given by
$G (s) H (s) = \frac{K}{s (s + 2) (s + 6)}, w h e r e k > 0.$ The value of K at the breakaway point of the root locus for the above system (rounded of to one decimal place) is

5

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Solution

The correct option is A 5
$G (s) H (s) = \frac{K}{s (s + 2) (s + 6)}$

Breakaway point = -0.9

$∴ ∣ ∣ ∣ \frac{K}{s (s + 2) (s + 6)} ∣ ∣ ∣ = 1$

$S = - 0.9$

$∴$ $K = 5$

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The loop transfer function of a negative feedback system is given by G(s)H(s)=Ks(s+2)(s+6),where k>0. The value of K at the breakaway point of the root locus for the above system (rounded of to one decimal place) is 5

The correct option is A 5G(s)H(s)=Ks(s+2)(s+6) Breakaway point = -0.9 ∴∣∣∣Ks(s+2)(s+6)∣∣∣=1 S=−0.9 ∴ K=5

The loop transfer function of a negative feedback system is given by
$G (s) H (s) = \frac{K}{s (s + 2) (s + 6)}, w h e r e k > 0.$ The value of K at the breakaway point of the root locus for the above system (rounded of to one decimal place) is

5

The correct option is A 5
$G (s) H (s) = \frac{K}{s (s + 2) (s + 6)}$

Breakaway point = -0.9

$∴ ∣ ∣ ∣ \frac{K}{s (s + 2) (s + 6)} ∣ ∣ ∣ = 1$

$S = - 0.9$

$∴$ $K = 5$