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Pascal's Law

The lower end...

Question

The lower end of a capillary tube of diameter $2.00 m m$ is dipped $8.00 c m$ surface of water in a beaker. What is the pressure required in the tube in order to below a hemisphere bubble at its end in water.

1.02 \times 10^{4} P a

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1.02 \times 10^{5} P a

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1.02 \times 10^{3} P a

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1.02 \times 10^{2} P a

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Solution

The correct option is B $1.02 \times 10^{5} P a$

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Similar questions

2.00

8.00

= 10^{3}

m^{- 3}

= 7.3 \times 10^{- 2}

m^{- 1}

= 1.01 \times 10^{5}

10 c m

2 m m

7.30 \times 10^{- 2} N / m

1 a t m o s p h e r i c p r e s s u r e = 10^{5} P a

= 1000 k g / m^{3}

[T_{w a t e r} = 7.3 \times 10^{- 3} N m^{- 1}, ρ_{w a t e r} = 1000 k g m^{- 3} a n d 1 a t m = 1.01 \times 10^{5} P a a n d g = 9.8 m s^{- 2}]

12 c m

3 c m

x c m

x

1.01146 \times 10^{x}

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