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Question

The lowest energy X-rays having λ=3.055×108 m. Which of the following statements is/are true?

A
The minimum difference in energy between two Bohr's orbits such that an electronic transition would correspond to the emission of an X-ray is 6.52×1018 J
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B
For Z=2 the transiton that corresponds to the above radiation is n=2 to n=1
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C
For Z=2 the transiton that corresponds to the above radiation is n=3 to n=2
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D
The minimum difference in energy between two Bohr's orbits such that an electronic transition would correspond to the emission of an X-ray is 1.65×1018 J
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Solution

The correct options are
A The minimum difference in energy between two Bohr's orbits such that an electronic transition would correspond to the emission of an X-ray is 6.52×1018 J
B For Z=2 the transiton that corresponds to the above radiation is n=2 to n=1
ΔE=hcλ=(6.63×1034 J.s)×(3×108 m/s)3.055×108 m
=6.52×1018 J
ΔEH=34(2.176×1018) J
=1.63×1018
ΔE=ΔEH(Z)2
Z2=ΔEΔEH=6.52×10181.63×1018=4
Z=2

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