The lowest value of angular momentum of an electron for the given value of magnetic quantum -1, 0, +1 is:

\frac{\sqrt{3 h}}{π}

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h / π

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2 h / π

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\frac{3 h}{π}

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Solution

The correct option is B $h / π$
If, magnetic quantum number $m = - 1, 0, + 1$ then, $l = 1$ .
$\Rightarrow m i n i m u m n = 2$
$a n g u l a r m o m e n t u m = \frac{n h}{2 π} = \frac{2 h}{2 π} = h / π$

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