The luminous flux of a monochromatic source of 1 W is 450 lumen $w a t t^{-} 1$ . Find the relative luminosity at the wavelength emitted.

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Solution

The luminous flux of the given source of 2 W is 450 lumen/watt

$∴$ Relative luminousity

Luminous flux of the source

$= \frac{o f g i v e n w a v e l e n g t h}{L u m i n o u s f l u x o f 555 n m}$

source of same power

$= \frac{450}{685} = 66$

[ $∴$ Since luminous flux of 555 nm source of 1 W = 685 lumen]

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