The $L U M O$ in $C O$ is

π - bonding

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π - antibonding

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σ - bonding

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σ - antibonding

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Solution

The correct option is B $π - antibonding$
HOMO- Highest occupied molecular orbital
LUMO- Lowest unoccupied molecular orbital

MO diagram of CO ligand is given below

From the diagram, we can say LUMO is $π$ - antibonding orbital.

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Similar questions

The LUMO in CO is

O_{2}

X_{2}

Δ A B C

{cos}^{2} A + {cos}^{2} B + {cos}^{2} C = cos A cos B + cos B cos C + cos C cos A

F e

(C O)_{3} F e (C O)_{3} F e (C O)_{3}

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