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Electric Circuit

The m rows ea...

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The m rows each containing n cells in series are joined in parallel. Maximum current is taken from this connection across an external resistance of 3 ohm. If the total no. of cells used = 24 and internal resistance of each cell is 0.5 ohm find the value of m and n.

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Q. To get maximum current in resistance of

3 Ω

n

parallel rows of

m

cells each connected in series. If the total no. of cells is

24

and the internal resistance is

0.5

Q. To get maximum current in a resistance of 3 ohms, one can use n rows of m cells (connected in series) connected in parallel. If the total number of cells is 24 and the internal resistance of a cell is 0.5 ohms then

24

cells, each having the same e.m.f. and

2

ohm internal resistance, are used to draw maximum current through an external resistance of

3

ohm. The cells should be connected :

Q. Twenty four cells each of emf 1.5V and internal resistance 0.5 ohms are to be connected to a 3 ohm resistance. For maximum current through this resistance the number of rows and number of columns that you connect these cells is?

^{'} n^{'}

cells, each of emf

^{'} e^{'}

and internal resistance

^{'} r^{'}

are joined in series to form a row.

^{'} m^{'}

such rows are connected in parallel to form a battery of

N = m n

cells. This battery is connected to an external resistance

^{'} R^{'}

Show that current

^{'} I^{'}

flowing through the external resistance

^{'} R^{'}

I = \frac{N e}{m R + n r}

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