The π-bonding involves overlap of d-orbitals of oxygen with d-orbitals of maganese
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B
There is no π-bonding
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C
The π-bonding involves overlap of p-orbitals of oxygen with d-orbitals of manganese
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D
The π-bonding involves overlap of p-orbitals of oxygen with p-orbitals of maganese
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Solution
The correct option is C The π-bonding involves overlap of p-orbitals of oxygen with d-orbitals of manganese ∙ Permanganate (MnO2−4) :
⇒π-bonds are of dπ−pπ type
In this manganate ion, two oxygen atoms are having a double bond with the manganese atom while remaining two oxygen atoms are having a single bond.
In this manganate ion, π bonds belong to p-orbitals of oxygen and with d-orbitals of manganese (dπ–pπ)
∙ Permanganate (MnO−4) :
⇒π-bonds are of dπ−pπ type.
In this permanganate ion, three oxygen atoms are having a double bond with manganese atom and one oxygen atom is having a single bond with manganese atom.
In this permanganate ion, π bonds belong to p-orbitals of oxygen and with d-orbitals of manganese (dπ–pπ)
As a result, the manganate and permanganate ions are tetrahedral, due to the π bonding involving overlap of p-orbitals of oxygen with d-orbitals of manganese.